5x^2-4=90

Solution for 5x^2-4=90 equation:

5x^2-4=90

We move all terms to the left:

5x^2-4-(90)=0

We add all the numbers together, and all the variables

5x^2-94=0

a = 5; b = 0; c = -94;
Δ = b2-4ac
Δ = 02-4·5·(-94)
Δ = 1880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1880}=\sqrt{4*470}=\sqrt{4}*\sqrt{470}=2\sqrt{470}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{470}}{2*5}=\frac{0-2\sqrt{470}}{10}
=-\frac{2\sqrt{470}}{10}
=-\frac{\sqrt{470}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{470}}{2*5}=\frac{0+2\sqrt{470}}{10}
=\frac{2\sqrt{470}}{10}
=\frac{\sqrt{470}}{5}
$